What are the solutions to the equation -25x^2+20x-4=0 ?

The solutions to the equation -25x^2+20x-4=0 are x= 2/5

Find the zeros of -25x^2+20x-4=0

The zeros of -25x^2+20x-4=0 are x= 2/5

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- 25 x^{2} + 20 x - 4 = 0

x = \frac{2}{5}

Decimal

x = 0.4

Solution steps

- 25 x^{2} + 20 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 25 ) ( - 4 )}{2 ( - 25 )}

2 0^{2} - 4 (- 25) (- 4) = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 ( - 25 )}

x = \frac{- 20}{2 ( - 25 )}

\frac{- 20}{2 ( - 25 )} = \frac{2}{5}

x = \frac{2}{5}

The solution to the quadratic equation is:

x = \frac{2}{5}

3 (x^{2} - 7) - 4 = - 7

y, y^{2} = x^{3} - x

4 x^{2} + 12 x - 5

2 - 25 x^{2} = 625 x^{2}

y, y^{2} - 3 x^{2} = 0

What are the solutions to the equation -25x^2+20x-4=0 ?
The solutions to the equation -25x^2+20x-4=0 are x= 2/5
Find the zeros of -25x^2+20x-4=0
The zeros of -25x^2+20x-4=0 are x= 2/5