What are the solutions to the equation -4x^2-13x-3=0 ?

The solutions to the equation -4x^2-13x-3=0 are x=-3,x=-1/4

Find the zeros of -4x^2-13x-3=0

The zeros of -4x^2-13x-3=0 are x=-3,x=-1/4

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- 4 x^{2} - 13 x - 3 = 0

x = - 3, x = - \frac{1}{4}

Decimal Notation

x = - 3, x = - 0.25

Solution steps

- 4 x^{2} - 13 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

(- 13)^{2} - 4 (- 4) (- 3) = 11

x_{1, 2} = \frac{- ( - 13 ) \pm 11}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 11}{2 ( - 4 )}, x_{2} = \frac{- ( - 13 ) - 11}{2 ( - 4 )}

x = \frac{- ( - 13 ) + 11}{2 ( - 4 )} : - 3

x = \frac{- ( - 13 ) - 11}{2 ( - 4 )} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = - 3, x = - \frac{1}{4}

x^{2} - 2 - 48 = 0

3 x^{2} + 2 x + 2

25 (5 x - 1)^{2} - 40 = - 4

y, x^{2} = 4 y^{2}

6 x^{2} - 30 x = 0

What are the solutions to the equation -4x^2-13x-3=0 ?
The solutions to the equation -4x^2-13x-3=0 are x=-3,x=-1/4
Find the zeros of -4x^2-13x-3=0
The zeros of -4x^2-13x-3=0 are x=-3,x=-1/4