What are the solutions to the equation y^2+10y+4=0 ?

The solutions to the equation y^2+10y+4=0 are y=-5+sqrt(21),y=-5-sqrt(21)

Find the zeros of y^2+10y+4=0

The zeros of y^2+10y+4=0 are y=-5+sqrt(21),y=-5-sqrt(21)

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y^{2} + 10 y + 4 = 0

y = - 5 + 21, y = - 5 - 21

Decimal Notation

y = - 0.41742 \dots, y = - 9.58257 \dots

Solution steps

y^{2} + 10 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 4 = 221

y_{1, 2} = \frac{- 10 \pm 2 21}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 10 + 2 21}{2 \cdot 1}, y_{2} = \frac{- 10 - 2 21}{2 \cdot 1}

y = \frac{- 10 + 2 21}{2 \cdot 1} : - 5 + 21

y = \frac{- 10 - 2 21}{2 \cdot 1} : - 5 - 21

The solutions to the quadratic equation are:

y = - 5 + 21, y = - 5 - 21

x^{2} + 15 x + 21 = 0

p^{2} + 9 p + 3 = - 4 p^{2}

y^{2} + 8.19 y - 15 = 0

3 (x + 11)^{2} + 12 = 0

x^{2} + 3^{2} = 2 5^{2}

What are the solutions to the equation y^2+10y+4=0 ?
The solutions to the equation y^2+10y+4=0 are y=-5+sqrt(21),y=-5-sqrt(21)
Find the zeros of y^2+10y+4=0
The zeros of y^2+10y+4=0 are y=-5+sqrt(21),y=-5-sqrt(21)