What are the solutions to the equation (4-x)^2=1 ?

The solutions to the equation (4-x)^2=1 are x=3,x=5

Find the zeros of (4-x)^2=1

The zeros of (4-x)^2=1 are x=3,x=5

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(4 - x)^{2} = 1

x = 3, x = 5

Solution steps

(4 - x)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 - x = 1 : x = 3

Solve

4 - x = - 1 : x = 5

The solutions to the quadratic equation are:

x = 3, x = 5

y, x^{2} + y^{2} = 6 x y

3 x^{2} + 6 x = 24

3 x^{2} + 168 = 36 x

v^{2} + 2 v + 4 = 3

2 x^{2} + 24 = 16 x

What are the solutions to the equation (4-x)^2=1 ?
The solutions to the equation (4-x)^2=1 are x=3,x=5
Find the zeros of (4-x)^2=1
The zeros of (4-x)^2=1 are x=3,x=5