What are the solutions to the equation 5t^2+15t+7=0 ?

The solutions to the equation 5t^2+15t+7=0 are t=(-15+sqrt(85))/(10),t=(-15-sqrt(85))/(10)

Find the zeros of 5t^2+15t+7=0

The zeros of 5t^2+15t+7=0 are t=(-15+sqrt(85))/(10),t=(-15-sqrt(85))/(10)

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5 t^{2} + 15 t + 7 = 0

t = \frac{- 15 + 85}{10}, t = \frac{- 15 - 85}{10}

Decimal Notation

t = - 0.57804 \dots, t = - 2.42195 \dots

Solution steps

5 t^{2} + 15 t + 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 \cdot 7}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 \cdot 7 = 85

t_{1, 2} = \frac{- 15 \pm 85}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 15 + 85}{2 \cdot 5}, t_{2} = \frac{- 15 - 85}{2 \cdot 5}

t = \frac{- 15 + 85}{2 \cdot 5} : \frac{- 15 + 85}{10}

t = \frac{- 15 - 85}{2 \cdot 5} : \frac{- 15 - 85}{10}

The solutions to the quadratic equation are:

t = \frac{- 15 + 85}{10}, t = \frac{- 15 - 85}{10}

9 d^{2} = 1

100 x^{2} - 10011 x - 10.11 = 0

(x + 2)^{2} - 4 x + 4 = 0

16 - x^{2} = 2 x + 1

x^{2} + 13 x = 30

What are the solutions to the equation 5t^2+15t+7=0 ?
The solutions to the equation 5t^2+15t+7=0 are t=(-15+sqrt(85))/(10),t=(-15-sqrt(85))/(10)
Find the zeros of 5t^2+15t+7=0
The zeros of 5t^2+15t+7=0 are t=(-15+sqrt(85))/(10),t=(-15-sqrt(85))/(10)