What are the solutions to the equation 5x-5+2x^2=2 ?

The solutions to the equation 5x-5+2x^2=2 are x=1,x=-7/2

Find the zeros of 5x-5+2x^2=2

The zeros of 5x-5+2x^2=2 are x=1,x=-7/2

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5 x - 5 + 2 x^{2} = 2

x = 1, x = - \frac{7}{2}

Decimal Notation

x = 1, x = - 3.5

Solution steps

5 x - 5 + 2 x^{2} = 2

Move

2

to the left side

2 x^{2} + 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 7) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 \cdot 2}, x_{2} = \frac{- 5 - 9}{2 \cdot 2}

x = \frac{- 5 + 9}{2 \cdot 2} : 1

x = \frac{- 5 - 9}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{7}{2}

2 x^{2} + 16 x + 11

12 x^{2} - 60 x + 48 = 0

- x^{2} + 10 x - 15 = 1

y, - 5 x^{2} y - 3 y - 6 y^{2} = 3 x

0.012552 x^{2} + 0.666 x = 12.98

What are the solutions to the equation 5x-5+2x^2=2 ?
The solutions to the equation 5x-5+2x^2=2 are x=1,x=-7/2
Find the zeros of 5x-5+2x^2=2
The zeros of 5x-5+2x^2=2 are x=1,x=-7/2