What are the solutions to the equation d^2-9d+11=0 ?

The solutions to the equation d^2-9d+11=0 are d=(9+sqrt(37))/2 ,d=(9-sqrt(37))/2

Find the zeros of d^2-9d+11=0

The zeros of d^2-9d+11=0 are d=(9+sqrt(37))/2 ,d=(9-sqrt(37))/2

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d^{2} - 9 d + 11 = 0

d = \frac{9 + 37}{2}, d = \frac{9 - 37}{2}

Decimal Notation

d = 7.54138 \dots, d = 1.45861 \dots

Solution steps

d^{2} - 9 d + 11 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 11 = 37

d_{1, 2} = \frac{- ( - 9 ) \pm 37}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- ( - 9 ) + 37}{2 \cdot 1}, d_{2} = \frac{- ( - 9 ) - 37}{2 \cdot 1}

d = \frac{- ( - 9 ) + 37}{2 \cdot 1} : \frac{9 + 37}{2}

d = \frac{- ( - 9 ) - 37}{2 \cdot 1} : \frac{9 - 37}{2}

The solutions to the quadratic equation are:

d = \frac{9 + 37}{2}, d = \frac{9 - 37}{2}

n^{2} - 6 n = 0

x, x^{2} - y^{2} - z^{2} = 4

5 r^{2} + r - 2 = 0

y, x^{2} + y^{2} = - 2

1 2^{2} + 2 0^{2} = x^{2}

What are the solutions to the equation d^2-9d+11=0 ?
The solutions to the equation d^2-9d+11=0 are d=(9+sqrt(37))/2 ,d=(9-sqrt(37))/2
Find the zeros of d^2-9d+11=0
The zeros of d^2-9d+11=0 are d=(9+sqrt(37))/2 ,d=(9-sqrt(37))/2