What are the solutions to the equation solvefor x,x(2x+1)=0 ?

The solutions to the equation solvefor x,x(2x+1)=0 are x=0,x=-1/2

Find the zeros of solvefor x,x(2x+1)=0

The zeros of solvefor x,x(2x+1)=0 are x=0,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x (2 x + 1) = 0

x = 0, x = - \frac{1}{2}

Decimal Notation

x = 0, x = - 0.5

Solution steps

x (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{2}

10 x^{2} + 125 = 5 x^{2} + 215

6 x^{2} + 125 = 5 (x^{2} + 25)

4 x^{2} + 5 x = - 1

9 (x^{2} - 2) - 13 = - 15

(17 - y)^{2} + y^{2} = 145

What are the solutions to the equation solvefor x,x(2x+1)=0 ?
The solutions to the equation solvefor x,x(2x+1)=0 are x=0,x=-1/2
Find the zeros of solvefor x,x(2x+1)=0
The zeros of solvefor x,x(2x+1)=0 are x=0,x=-1/2