What are the solutions to the equation 16(4+2x)^2-47=2 ?

The solutions to the equation 16(4+2x)^2-47=2 are x=-9/8 ,x=-23/8

Find the zeros of 16(4+2x)^2-47=2

The zeros of 16(4+2x)^2-47=2 are x=-9/8 ,x=-23/8

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16 (4 + 2 x)^{2} - 47 = 2

x = - \frac{9}{8}, x = - \frac{23}{8}

Decimal Notation

x = - 1.125, x = - 2.875

Solution steps

16 (4 + 2 x)^{2} - 47 = 2

Move

47

to the right side

16 (4 + 2 x)^{2} = 49

Divide both sides by

16

(4 + 2 x)^{2} = \frac{49}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 + 2 x = \frac{49}{16} : x = - \frac{9}{8}

Solve

4 + 2 x = - \frac{49}{16} : x = - \frac{23}{8}

The solutions to the quadratic equation are:

x = - \frac{9}{8}, x = - \frac{23}{8}

3 x^{2} + 10 x - 4 = - x

- 3 x^{2} - 6 x + 15 = 0

x^{2} - 16 x + 64

x^{2} - 18 x + 82 = 2

\frac{x ^{2}}{4} + \frac{x}{2} = 2

What are the solutions to the equation 16(4+2x)^2-47=2 ?
The solutions to the equation 16(4+2x)^2-47=2 are x=-9/8 ,x=-23/8
Find the zeros of 16(4+2x)^2-47=2
The zeros of 16(4+2x)^2-47=2 are x=-9/8 ,x=-23/8