What are the solutions to the equation roots x^2-3x+4 ?

The solutions to the equation roots x^2-3x+4 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2

Find the zeros of roots x^2-3x+4

The zeros of roots x^2-3x+4 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2

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roots

x^{2} - 3 x + 4

x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

Solution steps

x^{2} - 3 x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 4 : 7 i

x_{1, 2} = \frac{- ( - 3 ) \pm 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7 i}{2 \cdot 1} : \frac{3}{2} + i \frac{7}{2}

x = \frac{- ( - 3 ) - 7 i}{2 \cdot 1} : \frac{3}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

x^{2} - 3 x - 2

9 = - 2 x^{2} + 3 x

6 x^{2} - 60 x + 54 = 0

11 q^{2} - 44 = 0

14 x^{2} - 7 = 25

What are the solutions to the equation roots x^2-3x+4 ?
The solutions to the equation roots x^2-3x+4 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2
Find the zeros of roots x^2-3x+4
The zeros of roots x^2-3x+4 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2