What are the solutions to the equation 4(r-1)^2=8 ?

The solutions to the equation 4(r-1)^2=8 are r=sqrt(2)+1,r=-sqrt(2)+1

Find the zeros of 4(r-1)^2=8

The zeros of 4(r-1)^2=8 are r=sqrt(2)+1,r=-sqrt(2)+1

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4 (r - 1)^{2} = 8

r = 2 + 1, r = - 2 + 1

Decimal Notation

r = 2.41421 \dots, r = - 0.41421 \dots

Solution steps

4 (r - 1)^{2} = 8

Divide both sides by

4

(r - 1)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

r - 1 = 2 : r = 2 + 1

Solve

r - 1 = - 2 : r = - 2 + 1

The solutions to the quadratic equation are:

r = 2 + 1, r = - 2 + 1

(5 + x) (x + 1) = 4 (3 x - 4) + (x + 1) (3 x - 4)

4 x^{2} + 36 x = - 77

4 x^{2} + 36 x = - 73

x + 2 = x^{2} + 2 x

9 x^{2} + 6 x = - 1

What are the solutions to the equation 4(r-1)^2=8 ?
The solutions to the equation 4(r-1)^2=8 are r=sqrt(2)+1,r=-sqrt(2)+1
Find the zeros of 4(r-1)^2=8
The zeros of 4(r-1)^2=8 are r=sqrt(2)+1,r=-sqrt(2)+1