What are the solutions to the equation factor 12x^2-26x-7=3x+1 ?

The solutions to the equation factor 12x^2-26x-7=3x+1 are x=-1/4 ,x= 8/3

Find the zeros of factor 12x^2-26x-7=3x+1

The zeros of factor 12x^2-26x-7=3x+1 are x=-1/4 ,x= 8/3

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12 x^{2} - 26 x - 7 = 3 x + 1

x = - \frac{1}{4}, x = \frac{8}{3}

Decimal Notation

x = - 0.25, x = 2.66666 \dots

Solution steps

12 x^{2} - 26 x - 7 = 3 x + 1

Move

1

to the left side

12 x^{2} - 26 x - 8 = 3 x

Move

3 x

to the left side

12 x^{2} - 29 x - 8 = 0

Factor

12 x^{2} - 29 x - 8 : (4 x + 1) (3 x - 8)

(4 x + 1) (3 x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or 3 x - 8 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

3 x - 8 = 0 : x = \frac{8}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = \frac{8}{3}

3 x^{2} + 20 x + 16 = 6 x^{2} + 32 x + 28

(x + 5)^{2} = (5 - x)^{2} + (5 - x)^{2}

(- x + 2) (4 x + 4) = 0

a^{2} - 49 = 0

2 x^{2} + 13 x = - 6

What are the solutions to the equation factor 12x^2-26x-7=3x+1 ?
The solutions to the equation factor 12x^2-26x-7=3x+1 are x=-1/4 ,x= 8/3
Find the zeros of factor 12x^2-26x-7=3x+1
The zeros of factor 12x^2-26x-7=3x+1 are x=-1/4 ,x= 8/3