What are the solutions to the equation 2x^2+4x+11=0 ?

The solutions to the equation 2x^2+4x+11=0 are x=-1+i(3sqrt(2))/2 ,x=-1-i(3sqrt(2))/2

Find the zeros of 2x^2+4x+11=0

The zeros of 2x^2+4x+11=0 are x=-1+i(3sqrt(2))/2 ,x=-1-i(3sqrt(2))/2

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2 x^{2} + 4 x + 11 = 0

x = - 1 + i \frac{3 2}{2}, x = - 1 - i \frac{3 2}{2}

Solution steps

2 x^{2} + 4 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 11}{2 \cdot 2}

Simplify

4^{2} - 4 \cdot 2 \cdot 11 : 62 i

x_{1, 2} = \frac{- 4 \pm 6 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 6 2 i}{2 \cdot 2}, x_{2} = \frac{- 4 - 6 2 i}{2 \cdot 2}

x = \frac{- 4 + 6 2 i}{2 \cdot 2} : - 1 + i \frac{3 2}{2}

x = \frac{- 4 - 6 2 i}{2 \cdot 2} : - 1 - i \frac{3 2}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{3 2}{2}, x = - 1 - i \frac{3 2}{2}

a, n = 4 a^{2} - m

x^{2} - 5 x - 6

3 x^{2} - 31 x + 60 = 0

y, 3 x^{2} - 3 + 3 y^{2} = 6 x y

(\frac{x}{3})^{2} = 81

What are the solutions to the equation 2x^2+4x+11=0 ?
The solutions to the equation 2x^2+4x+11=0 are x=-1+i(3sqrt(2))/2 ,x=-1-i(3sqrt(2))/2
Find the zeros of 2x^2+4x+11=0
The zeros of 2x^2+4x+11=0 are x=-1+i(3sqrt(2))/2 ,x=-1-i(3sqrt(2))/2