What are the solutions to the equation -s^2-2s+5=0 ?

The solutions to the equation -s^2-2s+5=0 are s=-1-sqrt(6),s=sqrt(6)-1

Find the zeros of -s^2-2s+5=0

The zeros of -s^2-2s+5=0 are s=-1-sqrt(6),s=sqrt(6)-1

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- s^{2} - 2 s + 5 = 0

s = - 1 - 6, s = 6 - 1

Decimal Notation

s = - 3.44948 \dots, s = 1.44948 \dots

Solution steps

- s^{2} - 2 s + 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 5 = 26

s_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 ( - 1 )}

Separate the solutions

s_{1} = \frac{- ( - 2 ) + 2 6}{2 ( - 1 )}, s_{2} = \frac{- ( - 2 ) - 2 6}{2 ( - 1 )}

s = \frac{- ( - 2 ) + 2 6}{2 ( - 1 )} : - 1 - 6

s = \frac{- ( - 2 ) - 2 6}{2 ( - 1 )} : 6 - 1

The solutions to the quadratic equation are:

s = - 1 - 6, s = 6 - 1

y, 40 x^{2} + 3 y^{2} - 7 x + y + 1 = 0

t^{2} + 6 t - 4 = 0

x^{2} + 6 x + 19 = 4 x

10 x^{2} = 80 x

x^{2} + 20 x + 104 = 0

What are the solutions to the equation -s^2-2s+5=0 ?
The solutions to the equation -s^2-2s+5=0 are s=-1-sqrt(6),s=sqrt(6)-1
Find the zeros of -s^2-2s+5=0
The zeros of -s^2-2s+5=0 are s=-1-sqrt(6),s=sqrt(6)-1