What are the solutions to the equation roots 2x^2+3x-1 ?

The solutions to the equation roots 2x^2+3x-1 are x=(-3+sqrt(17))/4 ,x=(-3-sqrt(17))/4

Find the zeros of roots 2x^2+3x-1

The zeros of roots 2x^2+3x-1 are x=(-3+sqrt(17))/4 ,x=(-3-sqrt(17))/4

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roots

2 x^{2} + 3 x - 1

x = \frac{- 3 + 17}{4}, x = \frac{- 3 - 17}{4}

Solution steps

2 x^{2} + 3 x - 1

The roots are the intercepts with the x-axis

(y = 0)

2 x^{2} + 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 1) = 17

x_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 17}{2 \cdot 2}, x_{2} = \frac{- 3 - 17}{2 \cdot 2}

x = \frac{- 3 + 17}{2 \cdot 2} : \frac{- 3 + 17}{4}

x = \frac{- 3 - 17}{2 \cdot 2} : \frac{- 3 - 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 17}{4}, x = \frac{- 3 - 17}{4}

25 x^{2} - 10 x = - 1

x, y = 2 x^{2} - 12 x - 11

96 x^{2} + 660 x - 84 = 0

x^{2} - 4 x + 8 = 3

x^{2} + 2 = 4 x - 1

What are the solutions to the equation roots 2x^2+3x-1 ?
The solutions to the equation roots 2x^2+3x-1 are x=(-3+sqrt(17))/4 ,x=(-3-sqrt(17))/4
Find the zeros of roots 2x^2+3x-1
The zeros of roots 2x^2+3x-1 are x=(-3+sqrt(17))/4 ,x=(-3-sqrt(17))/4