What are the solutions to the equation factor 5k^2-9k+18=4k^2 ?

The solutions to the equation factor 5k^2-9k+18=4k^2 are k=3,k=6

Find the zeros of factor 5k^2-9k+18=4k^2

The zeros of factor 5k^2-9k+18=4k^2 are k=3,k=6

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5 k^{2} - 9 k + 18 = 4 k^{2}

k = 3, k = 6

Solution steps

5 k^{2} - 9 k + 18 = 4 k^{2}

Move

4 k^{2}

to the left side

k^{2} - 9 k + 18 = 0

Factor

k^{2} - 9 k + 18 : (k - 3) (k - 6)

(k - 3) (k - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

k - 3 = 0 or k - 6 = 0

Solve

k - 3 = 0 : k = 3

Solve

k - 6 = 0 : k = 6

The solutions to the quadratic equation are:

k = 3, k = 6

0 = 4 x^{2} - 16 x

10 x - \frac{5}{2} x^{2} = 10

x^{2} + 1.2 x + 1 = 0

h = \frac{( s ^{2} )}{b}

y, x^{2} y - x y^{2} = 2

What are the solutions to the equation factor 5k^2-9k+18=4k^2 ?
The solutions to the equation factor 5k^2-9k+18=4k^2 are k=3,k=6
Find the zeros of factor 5k^2-9k+18=4k^2
The zeros of factor 5k^2-9k+18=4k^2 are k=3,k=6