What are the solutions to the equation 13x^2+78x=0 ?

The solutions to the equation 13x^2+78x=0 are x=0,x=-6

Find the zeros of 13x^2+78x=0

The zeros of 13x^2+78x=0 are x=0,x=-6

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13 x^{2} + 78 x = 0

x = 0, x = - 6

Solution steps

13 x^{2} + 78 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 78 \pm 7 8 ^{2} - 4 \cdot 13 \cdot 0}{2 \cdot 13}

7 8^{2} - 4 \cdot 13 \cdot 0 = 78

x_{1, 2} = \frac{- 78 \pm 78}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- 78 + 78}{2 \cdot 13}, x_{2} = \frac{- 78 - 78}{2 \cdot 13}

x = \frac{- 78 + 78}{2 \cdot 13} : 0

x = \frac{- 78 - 78}{2 \cdot 13} : - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

x, x^{2} + 18 x + 81 = 25

(x - 1)^{2} - 25

20 x^{2} + 41 x + 20 = 0

3 a^{2} - 4 a = 4

6 x^{2} - 3 x = 2, y - 5 - 2 x^{2} + x = y - 4

What are the solutions to the equation 13x^2+78x=0 ?
The solutions to the equation 13x^2+78x=0 are x=0,x=-6
Find the zeros of 13x^2+78x=0
The zeros of 13x^2+78x=0 are x=0,x=-6