What are the solutions to the equation -5v^2+9v+1=-6v^2 ?

The solutions to the equation -5v^2+9v+1=-6v^2 are v=(-9+sqrt(77))/2 ,v=(-9-sqrt(77))/2

Find the zeros of -5v^2+9v+1=-6v^2

The zeros of -5v^2+9v+1=-6v^2 are v=(-9+sqrt(77))/2 ,v=(-9-sqrt(77))/2

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- 5 v^{2} + 9 v + 1 = - 6 v^{2}

v = \frac{- 9 + 77}{2}, v = \frac{- 9 - 77}{2}

Decimal Notation

v = - 0.11251 \dots, v = - 8.88748 \dots

Solution steps

- 5 v^{2} + 9 v + 1 = - 6 v^{2}

Move

6 v^{2}

to the left side

v^{2} + 9 v + 1 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 1 = 77

v_{1, 2} = \frac{- 9 \pm 77}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 9 + 77}{2 \cdot 1}, v_{2} = \frac{- 9 - 77}{2 \cdot 1}

v = \frac{- 9 + 77}{2 \cdot 1} : \frac{- 9 + 77}{2}

v = \frac{- 9 - 77}{2 \cdot 1} : \frac{- 9 - 77}{2}

The solutions to the quadratic equation are:

v = \frac{- 9 + 77}{2}, v = \frac{- 9 - 77}{2}

3 x^{2} + 28 x + 49 = 0

d^{2} + 10 d + 28 = 3

x^{2} + 61 = 1 - 17 x

9 x^{2} + 19 = 24 x

- 3 x^{2} + 5 x - 11 = 0

What are the solutions to the equation -5v^2+9v+1=-6v^2 ?
The solutions to the equation -5v^2+9v+1=-6v^2 are v=(-9+sqrt(77))/2 ,v=(-9-sqrt(77))/2
Find the zeros of -5v^2+9v+1=-6v^2
The zeros of -5v^2+9v+1=-6v^2 are v=(-9+sqrt(77))/2 ,v=(-9-sqrt(77))/2