What are the solutions to the equation roots a^2+2ab+b^2-x^2 ?

The solutions to the equation roots a^2+2ab+b^2-x^2 are x=a+b,x=-a-b

Find the zeros of roots a^2+2ab+b^2-x^2

The zeros of roots a^2+2ab+b^2-x^2 are x=a+b,x=-a-b

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roots

a^{2} + 2 ab + b^{2} - x^{2}

x = a + b, x = - a - b

Solution steps

a^{2} + 2 ab + b^{2} - x^{2}

The roots are the intercepts with the x-axis

(y = 0)

a^{2} + 2 ab + b^{2} - x^{2} = 0

Move

a^{2}

to the right side

2 ab + b^{2} - x^{2} = - a^{2}

Move

2 ab

to the right side

b^{2} - x^{2} = - a^{2} - 2 ab

Move

b^{2}

to the right side

- x^{2} = - a^{2} - 2 ab - b^{2}

Divide both sides by

- 1

x^{2} = a^{2} + 2 ab + b^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = a^{2} + 2 ab + b^{2}, x = - a^{2} + 2 ab + b^{2}

Simplify

a^{2} + 2 ab + b^{2} : a + b

Simplify

- a^{2} + 2 ab + b^{2} : - a - b

x = a + b, x = - a - b

3.02 x^{2} + 16 x - 7.02 = 0

x^{2} + x - 12 = x + 4

16 x^{2} = 81

x^{2} - 5 x + 24 = 0

- 4 x^{2} + 24 x - 35 = 0

What are the solutions to the equation roots a^2+2ab+b^2-x^2 ?
The solutions to the equation roots a^2+2ab+b^2-x^2 are x=a+b,x=-a-b
Find the zeros of roots a^2+2ab+b^2-x^2
The zeros of roots a^2+2ab+b^2-x^2 are x=a+b,x=-a-b