What are the solutions to the equation 3k^2+6k=105 ?

The solutions to the equation 3k^2+6k=105 are k=5,k=-7

Find the zeros of 3k^2+6k=105

The zeros of 3k^2+6k=105 are k=5,k=-7

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3 k^{2} + 6 k = 105

k = 5, k = - 7

Solution steps

3 k^{2} + 6 k = 105

Move

105

to the left side

3 k^{2} + 6 k - 105 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 105 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 105) = 36

k_{1, 2} = \frac{- 6 \pm 36}{2 \cdot 3}

Separate the solutions

k_{1} = \frac{- 6 + 36}{2 \cdot 3}, k_{2} = \frac{- 6 - 36}{2 \cdot 3}

k = \frac{- 6 + 36}{2 \cdot 3} : 5

k = \frac{- 6 - 36}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

k = 5, k = - 7

x^{2} + 4 x - 5

3 (3 x + 6)^{2} - 46 = 5

- 2 x^{2} - x + 15 = 0

x, 3 x^{2} + 6 x + 1 = 0

m^{2} + 2 m + 2 = 0

What are the solutions to the equation 3k^2+6k=105 ?
The solutions to the equation 3k^2+6k=105 are k=5,k=-7
Find the zeros of 3k^2+6k=105
The zeros of 3k^2+6k=105 are k=5,k=-7