What are the solutions to the equation 4r^2-8r=96 ?

The solutions to the equation 4r^2-8r=96 are r=6,r=-4

Find the zeros of 4r^2-8r=96

The zeros of 4r^2-8r=96 are r=6,r=-4

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4 r^{2} - 8 r = 96

r = 6, r = - 4

Solution steps

4 r^{2} - 8 r = 96

Move

96

to the left side

4 r^{2} - 8 r - 96 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 96 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 96) = 40

r_{1, 2} = \frac{- ( - 8 ) \pm 40}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 40}{2 \cdot 4}, r_{2} = \frac{- ( - 8 ) - 40}{2 \cdot 4}

r = \frac{- ( - 8 ) + 40}{2 \cdot 4} : 6

r = \frac{- ( - 8 ) - 40}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

r = 6, r = - 4

x^{2} + a x + b

x, - x^{2} + y^{2} - z^{2} = 1

17 x^{2} + 8 x = 0

2 x^{2} - x - 18 = 0

x^{2} - 8 x + 17

What are the solutions to the equation 4r^2-8r=96 ?
The solutions to the equation 4r^2-8r=96 are r=6,r=-4
Find the zeros of 4r^2-8r=96
The zeros of 4r^2-8r=96 are r=6,r=-4