What are the solutions to the equation 30x^2-62x+28=0 ?

The solutions to the equation 30x^2-62x+28=0 are x= 7/5 ,x= 2/3

Find the zeros of 30x^2-62x+28=0

The zeros of 30x^2-62x+28=0 are x= 7/5 ,x= 2/3

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30 x^{2} - 62 x + 28 = 0

x = \frac{7}{5}, x = \frac{2}{3}

Decimal Notation

x = 1.4, x = 0.66666 \dots

Solution steps

30 x^{2} - 62 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 62 ) \pm ( - 62 ) ^{2} - 4 \cdot 30 \cdot 28}{2 \cdot 30}

(- 62)^{2} - 4 \cdot 30 \cdot 28 = 22

x_{1, 2} = \frac{- ( - 62 ) \pm 22}{2 \cdot 30}

Separate the solutions

x_{1} = \frac{- ( - 62 ) + 22}{2 \cdot 30}, x_{2} = \frac{- ( - 62 ) - 22}{2 \cdot 30}

x = \frac{- ( - 62 ) + 22}{2 \cdot 30} : \frac{7}{5}

x = \frac{- ( - 62 ) - 22}{2 \cdot 30} : \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{7}{5}, x = \frac{2}{3}

24 x - 9

\frac{5}{6} + \frac{1}{2}

(\frac{27}{8})^{\frac{1}{3}}

\frac{4 + 6 i}{1 + i}

\frac{4 - i}{2 + 3 i}

What are the solutions to the equation 30x^2-62x+28=0 ?
The solutions to the equation 30x^2-62x+28=0 are x= 7/5 ,x= 2/3
Find the zeros of 30x^2-62x+28=0
The zeros of 30x^2-62x+28=0 are x= 7/5 ,x= 2/3