What are the solutions to the equation 4x^2-20x=-45 ?

The solutions to the equation 4x^2-20x=-45 are x= 5/2+sqrt(5)i,x= 5/2-sqrt(5)i

Find the zeros of 4x^2-20x=-45

The zeros of 4x^2-20x=-45 are x= 5/2+sqrt(5)i,x= 5/2-sqrt(5)i

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4 x^{2} - 20 x = - 45

x = \frac{5}{2} + 5 i, x = \frac{5}{2} - 5 i

Solution steps

4 x^{2} - 20 x = - 45

Move

45

to the left side

4 x^{2} - 20 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 45}{2 \cdot 4}

Simplify

(- 20)^{2} - 4 \cdot 4 \cdot 45 : 85 i

x_{1, 2} = \frac{- ( - 20 ) \pm 8 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8 5 i}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 8 5 i}{2 \cdot 4}

x = \frac{- ( - 20 ) + 8 5 i}{2 \cdot 4} : \frac{5}{2} + 5 i

x = \frac{- ( - 20 ) - 8 5 i}{2 \cdot 4} : \frac{5}{2} - 5 i

The solutions to the quadratic equation are:

x = \frac{5}{2} + 5 i, x = \frac{5}{2} - 5 i

y, x^{2} y^{3} = 1

x^{2} + 5 x - 6 = 0

(3 v - 2) (2 v + 1) = 3 v^{2} - 11 v - 10

5 x^{2} - 50 x + 125 = 0

3 (x + 1)^{2} = - 240

What are the solutions to the equation 4x^2-20x=-45 ?
The solutions to the equation 4x^2-20x=-45 are x= 5/2+sqrt(5)i,x= 5/2-sqrt(5)i
Find the zeros of 4x^2-20x=-45
The zeros of 4x^2-20x=-45 are x= 5/2+sqrt(5)i,x= 5/2-sqrt(5)i