What are the solutions to the equation 35x^2+17x=-2 ?

The solutions to the equation 35x^2+17x=-2 are x=-1/5 ,x=-2/7

Find the zeros of 35x^2+17x=-2

The zeros of 35x^2+17x=-2 are x=-1/5 ,x=-2/7

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35 x^{2} + 17 x = - 2

x = - \frac{1}{5}, x = - \frac{2}{7}

Decimal Notation

x = - 0.2, x = - 0.28571 \dots

Solution steps

35 x^{2} + 17 x = - 2

Move

2

to the left side

35 x^{2} + 17 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 35 \cdot 2}{2 \cdot 35}

1 7^{2} - 4 \cdot 35 \cdot 2 = 3

x_{1, 2} = \frac{- 17 \pm 3}{2 \cdot 35}

Separate the solutions

x_{1} = \frac{- 17 + 3}{2 \cdot 35}, x_{2} = \frac{- 17 - 3}{2 \cdot 35}

x = \frac{- 17 + 3}{2 \cdot 35} : - \frac{1}{5}

x = \frac{- 17 - 3}{2 \cdot 35} : - \frac{2}{7}

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - \frac{2}{7}

x^{2} + 18 x + 81 = 0

x^{2} + 18 x - 21 = 0

2 x^{2} - 4 x + 4 = 3 x

9 x^{2} = - 15 x

x^{2} - 121 = 0

What are the solutions to the equation 35x^2+17x=-2 ?
The solutions to the equation 35x^2+17x=-2 are x=-1/5 ,x=-2/7
Find the zeros of 35x^2+17x=-2
The zeros of 35x^2+17x=-2 are x=-1/5 ,x=-2/7