What are the solutions to the equation solvefor x,(x-a)^2+y^2=d^2 ?

The solutions to the equation solvefor x,(x-a)^2+y^2=d^2 are x=sqrt(d^2-y^2)+a,x=-sqrt(d^2-y^2)+a

Find the zeros of solvefor x,(x-a)^2+y^2=d^2

The zeros of solvefor x,(x-a)^2+y^2=d^2 are x=sqrt(d^2-y^2)+a,x=-sqrt(d^2-y^2)+a

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solve for

x, (x - a)^{2} + y^{2} = d^{2}

x = d^{2} - y^{2} + a, x = - d^{2} - y^{2} + a

Solution steps

(x - a)^{2} + y^{2} = d^{2}

Move

y^{2}

to the right side

(x - a)^{2} = d^{2} - y^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - a = d^{2} - y^{2} : x = d^{2} - y^{2} + a

Solve

x - a = - d^{2} - y^{2} : x = - d^{2} - y^{2} + a

The solutions to the quadratic equation are:

x = d^{2} - y^{2} + a, x = - d^{2} - y^{2} + a

3 x^{2} + (m + 2) x - 5 + m = 0

3 x^{2} - 6 x

y^{2} + 100 = 0

4 x^{2} - 11 = x^{2} - 11 + 9 x

x^{2} - 3 x + 6 = 2 x + 6

What are the solutions to the equation solvefor x,(x-a)^2+y^2=d^2 ?
The solutions to the equation solvefor x,(x-a)^2+y^2=d^2 are x=sqrt(d^2-y^2)+a,x=-sqrt(d^2-y^2)+a
Find the zeros of solvefor x,(x-a)^2+y^2=d^2
The zeros of solvefor x,(x-a)^2+y^2=d^2 are x=sqrt(d^2-y^2)+a,x=-sqrt(d^2-y^2)+a