What are the solutions to the equation (m-2)^2+3=28 ?

The solutions to the equation (m-2)^2+3=28 are m=7,m=-3

Find the zeros of (m-2)^2+3=28

The zeros of (m-2)^2+3=28 are m=7,m=-3

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(m - 2)^{2} + 3 = 28

m = 7, m = - 3

Solution steps

(m - 2)^{2} + 3 = 28

Move

3

to the right side

(m - 2)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

m - 2 = 25 : m = 7

Solve

m - 2 = - 25 : m = - 3

The solutions to the quadratic equation are:

m = 7, m = - 3

5 x^{2} + 11 x + 2 = 0

39 = - (\frac{x ^{2}}{200}) + x - 2

x^{2} - \frac{15}{81} = \frac{539}{891}

5 n^{2} + 1 = 0

3 k^{2} + 2 k = 2 k^{2} + 11 k

What are the solutions to the equation (m-2)^2+3=28 ?
The solutions to the equation (m-2)^2+3=28 are m=7,m=-3
Find the zeros of (m-2)^2+3=28
The zeros of (m-2)^2+3=28 are m=7,m=-3