What are the solutions to the equation x^2+3x-3=7x+9 ?

The solutions to the equation x^2+3x-3=7x+9 are x=6,x=-2

Find the zeros of x^2+3x-3=7x+9

The zeros of x^2+3x-3=7x+9 are x=6,x=-2

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x^{2} + 3 x - 3 = 7 x + 9

x = 6, x = - 2

Solution steps

x^{2} + 3 x - 3 = 7 x + 9

Move

9

to the left side

x^{2} + 3 x - 12 = 7 x

Move

7 x

to the left side

x^{2} - 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

x = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

x = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

x^{2} + 10 x - 12

x^{2} - 4 x = 77

- 60 x^{2} = 0

- 0.5 x^{2} + 0.75 x - 0.25 = 0

x^{2} - 6 = - 10

What are the solutions to the equation x^2+3x-3=7x+9 ?
The solutions to the equation x^2+3x-3=7x+9 are x=6,x=-2
Find the zeros of x^2+3x-3=7x+9
The zeros of x^2+3x-3=7x+9 are x=6,x=-2