What are the solutions to the equation 25t^2+20t+3=-1 ?

The solutions to the equation 25t^2+20t+3=-1 are t=-2/5

Find the zeros of 25t^2+20t+3=-1

The zeros of 25t^2+20t+3=-1 are t=-2/5

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25 t^{2} + 20 t + 3 = - 1

t = - \frac{2}{5}

Decimal Notation

t = - 0.4

Solution steps

25 t^{2} + 20 t + 3 = - 1

Move

1

to the left side

25 t^{2} + 20 t + 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

2 0^{2} - 4 \cdot 25 \cdot 4 = 0

t_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 25}

t = \frac{- 20}{2 \cdot 25}

\frac{- 20}{2 \cdot 25} = - \frac{2}{5}

t = - \frac{2}{5}

The solution to the quadratic equation is:

t = - \frac{2}{5}

0 = 4 x^{2} - 8 x + 3

2 x^{2} - 1 = 7

9 x^{2} = 12 x - 2

12 x^{2} - 92 x + 126 = 0

- \frac{2}{3} x^{2} + 6 = 0

What are the solutions to the equation 25t^2+20t+3=-1 ?
The solutions to the equation 25t^2+20t+3=-1 are t=-2/5
Find the zeros of 25t^2+20t+3=-1
The zeros of 25t^2+20t+3=-1 are t=-2/5