What are the solutions to the equation -5=-1/2 9.8x^2+2x ?

The solutions to the equation -5=-1/2 9.8x^2+2x are x=-(5(sqrt(102)-2))/(49),x=(5(2+sqrt(102)))/(49)

Find the zeros of -5=-1/2 9.8x^2+2x

The zeros of -5=-1/2 9.8x^2+2x are x=-(5(sqrt(102)-2))/(49),x=(5(2+sqrt(102)))/(49)

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- 5 = - \frac{1}{2} 9.8 x^{2} + 2 x

x = - \frac{5 ( 102 - 2 )}{49}, x = \frac{5 ( 2 + 102 )}{49}

Decimal Notation

x = - 0.82648 \dots, x = 1.23464 \dots

Solution steps

- 5 = - \frac{1}{2} \cdot 9.8 x^{2} + 2 x

Multiply both sides by

10

- 50 = - 49 x^{2} + 20 x

Switch sides

- 49 x^{2} + 20 x = - 50

Move

50

to the left side

- 49 x^{2} + 20 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 49 ) \cdot 50}{2 ( - 49 )}

2 0^{2} - 4 (- 49) \cdot 50 = 10102

x_{1, 2} = \frac{- 20 \pm 10 102}{2 ( - 49 )}

Separate the solutions

x_{1} = \frac{- 20 + 10 102}{2 ( - 49 )}, x_{2} = \frac{- 20 - 10 102}{2 ( - 49 )}

x = \frac{- 20 + 10 102}{2 ( - 49 )} : - \frac{5 ( 102 - 2 )}{49}

x = \frac{- 20 - 10 102}{2 ( - 49 )} : \frac{5 ( 2 + 102 )}{49}

The solutions to the quadratic equation are:

x = - \frac{5 ( 102 - 2 )}{49}, x = \frac{5 ( 2 + 102 )}{49}

x, z^{2} = x^{2} y + 4.02

9 y^{2} = - 30 y - 25

x^{2} + 2 x - 76 = 4

94 - q = q^{2}

3 x^{2} + 5 x - 2

What are the solutions to the equation -5=-1/2 9.8x^2+2x ?
The solutions to the equation -5=-1/2 9.8x^2+2x are x=-(5(sqrt(102)-2))/(49),x=(5(2+sqrt(102)))/(49)
Find the zeros of -5=-1/2 9.8x^2+2x
The zeros of -5=-1/2 9.8x^2+2x are x=-(5(sqrt(102)-2))/(49),x=(5(2+sqrt(102)))/(49)