What are the solutions to the equation 4.9t^2+6t+2=0 ?

The solutions to the equation 4.9t^2+6t+2=0 are t=-30/49+i(4sqrt(5))/(49),t=-30/49-i(4sqrt(5))/(49)

Find the zeros of 4.9t^2+6t+2=0

The zeros of 4.9t^2+6t+2=0 are t=-30/49+i(4sqrt(5))/(49),t=-30/49-i(4sqrt(5))/(49)

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4.9 t^{2} + 6 t + 2 = 0

t = - \frac{30}{49} + i \frac{4 5}{49}, t = - \frac{30}{49} - i \frac{4 5}{49}

Solution steps

4.9 t^{2} + 6 t + 2 = 0

Multiply both sides by

10

49 t^{2} + 60 t + 20 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 49 \cdot 20}{2 \cdot 49}

Simplify

6 0^{2} - 4 \cdot 49 \cdot 20 : 85 i

t_{1, 2} = \frac{- 60 \pm 8 5 i}{2 \cdot 49}

Separate the solutions

t_{1} = \frac{- 60 + 8 5 i}{2 \cdot 49}, t_{2} = \frac{- 60 - 8 5 i}{2 \cdot 49}

t = \frac{- 60 + 8 5 i}{2 \cdot 49} : - \frac{30}{49} + i \frac{4 5}{49}

t = \frac{- 60 - 8 5 i}{2 \cdot 49} : - \frac{30}{49} - i \frac{4 5}{49}

The solutions to the quadratic equation are:

t = - \frac{30}{49} + i \frac{4 5}{49}, t = - \frac{30}{49} - i \frac{4 5}{49}

x^{2} + 4 x - 12

y, x^{2} + 3 y^{2} - 4 x + 24 y = - 52

18 x - 6 = 9 x^{2}

y, x^{2} y^{2} + x y = 12

x^{2} - 5 x - 12 = - 5 x + 4

What are the solutions to the equation 4.9t^2+6t+2=0 ?
The solutions to the equation 4.9t^2+6t+2=0 are t=-30/49+i(4sqrt(5))/(49),t=-30/49-i(4sqrt(5))/(49)
Find the zeros of 4.9t^2+6t+2=0
The zeros of 4.9t^2+6t+2=0 are t=-30/49+i(4sqrt(5))/(49),t=-30/49-i(4sqrt(5))/(49)