What are the solutions to the equation 11y^2-12y+4=6y^2 ?

The solutions to the equation 11y^2-12y+4=6y^2 are y=2,y= 2/5

Find the zeros of 11y^2-12y+4=6y^2

The zeros of 11y^2-12y+4=6y^2 are y=2,y= 2/5

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11 y^{2} - 12 y + 4 = 6 y^{2}

y = 2, y = \frac{2}{5}

Decimal Notation

y = 2, y = 0.4

Solution steps

11 y^{2} - 12 y + 4 = 6 y^{2}

Move

6 y^{2}

to the left side

5 y^{2} - 12 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 \cdot 4 = 8

y_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 5}, y_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 5}

y = \frac{- ( - 12 ) + 8}{2 \cdot 5} : 2

y = \frac{- ( - 12 ) - 8}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

y = 2, y = \frac{2}{5}

x^{2} - 2 x - 2 = 0, x > 0

y, x^{2} y^{9} = 2

x^{2} - 10 x - 9

x^{2} - 10 x - 7

(- 0.02083 x^{2}) + 4 x - 170 = 0

What are the solutions to the equation 11y^2-12y+4=6y^2 ?
The solutions to the equation 11y^2-12y+4=6y^2 are y=2,y= 2/5
Find the zeros of 11y^2-12y+4=6y^2
The zeros of 11y^2-12y+4=6y^2 are y=2,y= 2/5