What are the solutions to the equation 25n^2-24n+6=n ?

The solutions to the equation 25n^2-24n+6=n are n= 3/5 ,n= 2/5

Find the zeros of 25n^2-24n+6=n

The zeros of 25n^2-24n+6=n are n= 3/5 ,n= 2/5

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25 n^{2} - 24 n + 6 = n

n = \frac{3}{5}, n = \frac{2}{5}

Decimal Notation

n = 0.6, n = 0.4

Solution steps

25 n^{2} - 24 n + 6 = n

Move

n

to the left side

25 n^{2} - 25 n + 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 25 \cdot 6}{2 \cdot 25}

(- 25)^{2} - 4 \cdot 25 \cdot 6 = 5

n_{1, 2} = \frac{- ( - 25 ) \pm 5}{2 \cdot 25}

Separate the solutions

n_{1} = \frac{- ( - 25 ) + 5}{2 \cdot 25}, n_{2} = \frac{- ( - 25 ) - 5}{2 \cdot 25}

n = \frac{- ( - 25 ) + 5}{2 \cdot 25} : \frac{3}{5}

n = \frac{- ( - 25 ) - 5}{2 \cdot 25} : \frac{2}{5}

The solutions to the quadratic equation are:

n = \frac{3}{5}, n = \frac{2}{5}

5 x^{2} - 12 x = 2 x^{2}

16 (4 - 2 x)^{2} = 9

(2 x + 3)^{2} = 3 x (x + 2)

22 c^{2} - 35 c + 12 = - 3 c^{2}

x^{2} - 12 = 0

What are the solutions to the equation 25n^2-24n+6=n ?
The solutions to the equation 25n^2-24n+6=n are n= 3/5 ,n= 2/5
Find the zeros of 25n^2-24n+6=n
The zeros of 25n^2-24n+6=n are n= 3/5 ,n= 2/5