What are the solutions to the equation completesquare x^2+4x=5 ?

The solutions to the equation completesquare x^2+4x=5 are x=1,x=-5

Find the zeros of completesquare x^2+4x=5

The zeros of completesquare x^2+4x=5 are x=1,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 x = 5

x = 1, x = - 5

Solution steps

x^{2} + 4 x = 5

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = 9

For

the solutions are

f (x) = a, - a

Solve

x + 2 = 9 : x = 1

Solve

x + 2 = - 9 : x = - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

3 x^{2} + 12 x = 7 x + 2

4 x^{2} - 9 = 0

x^{2} + 4 x - 4

350 x^{2} = 686

x^{2} + \frac{7}{3} - \frac{x ^{2} - 3}{9} = 3 x + 1

What are the solutions to the equation completesquare x^2+4x=5 ?
The solutions to the equation completesquare x^2+4x=5 are x=1,x=-5
Find the zeros of completesquare x^2+4x=5
The zeros of completesquare x^2+4x=5 are x=1,x=-5