What are the solutions to the equation 18x^2-6x-4=0 ?

The solutions to the equation 18x^2-6x-4=0 are x= 2/3 ,x=-1/3

Find the zeros of 18x^2-6x-4=0

The zeros of 18x^2-6x-4=0 are x= 2/3 ,x=-1/3

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18 x^{2} - 6 x - 4 = 0

x = \frac{2}{3}, x = - \frac{1}{3}

Decimal

x = 0.66666 \dots, x = - 0.33333 \dots

Solution steps

18 x^{2} - 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 18 ( - 4 )}{2 \cdot 18}

(- 6)^{2} - 4 \cdot 18 (- 4) = 18

x_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 18}, x_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 18}

x = \frac{- ( - 6 ) + 18}{2 \cdot 18} : \frac{2}{3}

x = \frac{- ( - 6 ) - 18}{2 \cdot 18} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{1}{3}

11 x^{2} - 24 x + 4 = 0

a^{2} - 2 = 0

2 y^{2} - 4 y - 1 = 0

25 x^{2} = 4

363 π - π h^{2} = 0

What are the solutions to the equation 18x^2-6x-4=0 ?
The solutions to the equation 18x^2-6x-4=0 are x= 2/3 ,x=-1/3
Find the zeros of 18x^2-6x-4=0
The zeros of 18x^2-6x-4=0 are x= 2/3 ,x=-1/3