What are the solutions to the equation p^2-10p-52=0 ?

The solutions to the equation p^2-10p-52=0 are p=5+sqrt(77),p=5-sqrt(77)

Find the zeros of p^2-10p-52=0

The zeros of p^2-10p-52=0 are p=5+sqrt(77),p=5-sqrt(77)

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p^{2} - 10 p - 52 = 0

p = 5 + 77, p = 5 - 77

Decimal Notation

p = 13.77496 \dots, p = - 3.77496 \dots

Solution steps

p^{2} - 10 p - 52 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 52 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 52) = 277

p_{1, 2} = \frac{- ( - 10 ) \pm 2 77}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 10 ) + 2 77}{2 \cdot 1}, p_{2} = \frac{- ( - 10 ) - 2 77}{2 \cdot 1}

p = \frac{- ( - 10 ) + 2 77}{2 \cdot 1} : 5 + 77

p = \frac{- ( - 10 ) - 2 77}{2 \cdot 1} : 5 - 77

The solutions to the quadratic equation are:

p = 5 + 77, p = 5 - 77

y, x^{2} + y^{3} = 4

5 x^{2} = 15 x

4 x^{2} + 57 = - 28 x

3 x^{2} - 136 x + 1300 = 0

4 x^{2} - 6 x + 2 = 5 + 5 x

What are the solutions to the equation p^2-10p-52=0 ?
The solutions to the equation p^2-10p-52=0 are p=5+sqrt(77),p=5-sqrt(77)
Find the zeros of p^2-10p-52=0
The zeros of p^2-10p-52=0 are p=5+sqrt(77),p=5-sqrt(77)