What are the solutions to the equation 4x=3x^2-7x+9 ?

The solutions to the equation 4x=3x^2-7x+9 are x=(11+sqrt(13))/6 ,x=(11-sqrt(13))/6

Find the zeros of 4x=3x^2-7x+9

The zeros of 4x=3x^2-7x+9 are x=(11+sqrt(13))/6 ,x=(11-sqrt(13))/6

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4 x = 3 x^{2} - 7 x + 9

x = \frac{11 + 13}{6}, x = \frac{11 - 13}{6}

Decimal Notation

x = 2.43425 \dots, x = 1.23240 \dots

Solution steps

4 x = 3 x^{2} - 7 x + 9

Switch sides

3 x^{2} - 7 x + 9 = 4 x

Move

4 x

to the left side

3 x^{2} - 11 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

(- 11)^{2} - 4 \cdot 3 \cdot 9 = 13

x_{1, 2} = \frac{- ( - 11 ) \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 13}{2 \cdot 3}, x_{2} = \frac{- ( - 11 ) - 13}{2 \cdot 3}

x = \frac{- ( - 11 ) + 13}{2 \cdot 3} : \frac{11 + 13}{6}

x = \frac{- ( - 11 ) - 13}{2 \cdot 3} : \frac{11 - 13}{6}

The solutions to the quadratic equation are:

x = \frac{11 + 13}{6}, x = \frac{11 - 13}{6}

8 x^{2} - 17 x = 4 x^{2} + 13 x

(x) = x^{2} - 4 x + 3

9 x^{2} = 4 x + 1

y, y^{2} - 3 y - 4 = 0

2 m^{2} - 7 m = 15

What are the solutions to the equation 4x=3x^2-7x+9 ?
The solutions to the equation 4x=3x^2-7x+9 are x=(11+sqrt(13))/6 ,x=(11-sqrt(13))/6
Find the zeros of 4x=3x^2-7x+9
The zeros of 4x=3x^2-7x+9 are x=(11+sqrt(13))/6 ,x=(11-sqrt(13))/6