What are the solutions to the equation x^2-2x+8=4x ?

The solutions to the equation x^2-2x+8=4x are x=4,x=2

Find the zeros of x^2-2x+8=4x

The zeros of x^2-2x+8=4x are x=4,x=2

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x^{2} - 2 x + 8 = 4 x

x = 4, x = 2

Solution steps

x^{2} - 2 x + 8 = 4 x

Move

4 x

to the left side

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

y, x^{2} y^{2} - 2 x^{2} y + x^{2} - 2 x + 1 = 0

x^{2} + 6 x = 7

0.000002 x^{2} - 0.06 x + 400 = 0

x^{2} = - 3 x + 10

x^{2} - 8 x + 10

What are the solutions to the equation x^2-2x+8=4x ?
The solutions to the equation x^2-2x+8=4x are x=4,x=2
Find the zeros of x^2-2x+8=4x
The zeros of x^2-2x+8=4x are x=4,x=2