What are the solutions to the equation 3x^2+7x=20 ?

The solutions to the equation 3x^2+7x=20 are x= 5/3 ,x=-4

Find the zeros of 3x^2+7x=20

The zeros of 3x^2+7x=20 are x= 5/3 ,x=-4

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3 x^{2} + 7 x = 20

x = \frac{5}{3}, x = - 4

Decimal Notation

x = 1.66666 \dots, x = - 4

Solution steps

3 x^{2} + 7 x = 20

Move

20

to the left side

3 x^{2} + 7 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 20) = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 3}, x_{2} = \frac{- 7 - 17}{2 \cdot 3}

x = \frac{- 7 + 17}{2 \cdot 3} : \frac{5}{3}

x = \frac{- 7 - 17}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 4

3 x^{2} + 7 x - 24 = 13 x

3 x^{2} - 8 x + 4 = 0

x - 8 = 7 (x - 2) x

- 8 - 5 n^{2} = - 88

- 1 = t - t^{2}

What are the solutions to the equation 3x^2+7x=20 ?
The solutions to the equation 3x^2+7x=20 are x= 5/3 ,x=-4
Find the zeros of 3x^2+7x=20
The zeros of 3x^2+7x=20 are x= 5/3 ,x=-4