What is (-10+3i)/(2i) ?

The solution to (-10+3i)/(2i) is 3/2+5i

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simplify (-10+3i)/(2i)

simplify

\frac{- 10 + 3 i}{2 i}

\frac{3}{2} + 5 i

Solution steps

\frac{- 10 + 3 i}{2 i}

Multiply by the conjugate

\frac{- i}{- i}

= \frac{( - 10 + 3 i ) ( - i )}{2 i ( - i )}

Simplify

\frac{( - 10 + 3 i ) ( - i )}{2 i ( - i )} : \frac{10 i + 3}{2}

= \frac{10 i + 3}{2}

Rewrite

10 i + 3

in standard complex form:

3 + 10 i

= \frac{3 + 10 i}{2}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{3}{2} + \frac{10}{2} i

Divide the numbers:

\frac{10}{2} = 5

= \frac{3}{2} + 5 i

\frac{7}{5} + \frac{8}{15} + \frac{11}{60}

- 6 x^{2} - 25 x - 25

(\frac{1}{4})^{- 2}

m^{4} + 10 m^{2} + 25

lo g_{3} (x) < 2