What are the solutions to the equation roots x^2-10x+25 ?

The solutions to the equation roots x^2-10x+25 are x=5

Find the zeros of roots x^2-10x+25

The zeros of roots x^2-10x+25 are x=5

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roots

x^{2} - 10 x + 25

x = 5

Solution steps

x^{2} - 10 x + 25

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

2 x^{2} - 80 = - 12 x

4 x^{2} + 4 x + 1

(x - 3)^{2} = 121

x^{2} + 10 x + 98 = 0

- 3 x^{2} - 30 x - 72 = 0

What are the solutions to the equation roots x^2-10x+25 ?
The solutions to the equation roots x^2-10x+25 are x=5
Find the zeros of roots x^2-10x+25
The zeros of roots x^2-10x+25 are x=5