What are the solutions to the equation x^2-0.2x-4.85=0 ?

The solutions to the equation x^2-0.2x-4.85=0 are x=(1+9sqrt(6))/(10),x=(1-9sqrt(6))/(10)

Find the zeros of x^2-0.2x-4.85=0

The zeros of x^2-0.2x-4.85=0 are x=(1+9sqrt(6))/(10),x=(1-9sqrt(6))/(10)

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x^{2} - 0.2 x - 4.85 = 0

x = \frac{1 + 9 6}{10}, x = \frac{1 - 9 6}{10}

Decimal Notation

x = 2.30454 \dots, x = - 2.10454 \dots

Solution steps

x^{2} - 0.2 x - 4.85 = 0

Multiply both sides by

100

100 x^{2} - 20 x - 485 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 100 ( - 485 )}{2 \cdot 100}

(- 20)^{2} - 4 \cdot 100 (- 485) = 1806

x_{1, 2} = \frac{- ( - 20 ) \pm 180 6}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 180 6}{2 \cdot 100}, x_{2} = \frac{- ( - 20 ) - 180 6}{2 \cdot 100}

x = \frac{- ( - 20 ) + 180 6}{2 \cdot 100} : \frac{1 + 9 6}{10}

x = \frac{- ( - 20 ) - 180 6}{2 \cdot 100} : \frac{1 - 9 6}{10}

The solutions to the quadratic equation are:

x = \frac{1 + 9 6}{10}, x = \frac{1 - 9 6}{10}

x^{2} = \frac{2}{3} x + \frac{16}{3}

y, x^{2} + y^{2} + 2 x y - 7 x - 6 y + 10 = 0

(1 - x) (1 - x) + 4 = 0

m^{2} + 11 m + 16 = 0

x^{2} - 10 x + c

What are the solutions to the equation x^2-0.2x-4.85=0 ?
The solutions to the equation x^2-0.2x-4.85=0 are x=(1+9sqrt(6))/(10),x=(1-9sqrt(6))/(10)
Find the zeros of x^2-0.2x-4.85=0
The zeros of x^2-0.2x-4.85=0 are x=(1+9sqrt(6))/(10),x=(1-9sqrt(6))/(10)