What are the solutions to the equation 3x^2-36x-47=0 ?

The solutions to the equation 3x^2-36x-47=0 are x=(18+sqrt(465))/3 ,x=(18-sqrt(465))/3

Find the zeros of 3x^2-36x-47=0

The zeros of 3x^2-36x-47=0 are x=(18+sqrt(465))/3 ,x=(18-sqrt(465))/3

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3 x^{2} - 36 x - 47 = 0

x = \frac{18 + 465}{3}, x = \frac{18 - 465}{3}

Decimal Notation

x = 13.18795 \dots, x = - 1.18795 \dots

Solution steps

3 x^{2} - 36 x - 47 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 ( - 47 )}{2 \cdot 3}

(- 36)^{2} - 4 \cdot 3 (- 47) = 2465

x_{1, 2} = \frac{- ( - 36 ) \pm 2 465}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 2 465}{2 \cdot 3}, x_{2} = \frac{- ( - 36 ) - 2 465}{2 \cdot 3}

x = \frac{- ( - 36 ) + 2 465}{2 \cdot 3} : \frac{18 + 465}{3}

x = \frac{- ( - 36 ) - 2 465}{2 \cdot 3} : \frac{18 - 465}{3}

The solutions to the quadratic equation are:

x = \frac{18 + 465}{3}, x = \frac{18 - 465}{3}

x^{2} - 18 x = - 62

3 x^{2} + 7 x - 1748 = 0

- 3 x^{2} + 9 x = 1

- 3 x^{2} + 9 x = 7

x^{2} + 1 = 4 x + 3

What are the solutions to the equation 3x^2-36x-47=0 ?
The solutions to the equation 3x^2-36x-47=0 are x=(18+sqrt(465))/3 ,x=(18-sqrt(465))/3
Find the zeros of 3x^2-36x-47=0
The zeros of 3x^2-36x-47=0 are x=(18+sqrt(465))/3 ,x=(18-sqrt(465))/3