What are the solutions to the equation (8+d)^2+81=100 ?

The solutions to the equation (8+d)^2+81=100 are d=sqrt(19)-8,d=-sqrt(19)-8

Find the zeros of (8+d)^2+81=100

The zeros of (8+d)^2+81=100 are d=sqrt(19)-8,d=-sqrt(19)-8

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(8 + d)^{2} + 81 = 100

d = 19 - 8, d = - 19 - 8

Decimal Notation

d = - 3.64110 \dots, d = - 12.35889 \dots

Solution steps

(8 + d)^{2} + 81 = 100

Move

81

to the right side

(8 + d)^{2} = 19

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

8 + d = 19 : d = 19 - 8

Solve

8 + d = - 19 : d = - 19 - 8

The solutions to the quadratic equation are:

d = 19 - 8, d = - 19 - 8

20 x - 5 x^{2} = 0

x^{2} - 10 x = - 345

x, x^{2} + y^{2} + 4 z^{2} = 10

y^{2} - 6 y - 3 = 0

2 x + 2 = x^{2} - 2 x - 43

What are the solutions to the equation (8+d)^2+81=100 ?
The solutions to the equation (8+d)^2+81=100 are d=sqrt(19)-8,d=-sqrt(19)-8
Find the zeros of (8+d)^2+81=100
The zeros of (8+d)^2+81=100 are d=sqrt(19)-8,d=-sqrt(19)-8