What are the solutions to the equation u^2-6u+1=0 ?

The solutions to the equation u^2-6u+1=0 are u=3+2sqrt(2),u=3-2sqrt(2)

Find the zeros of u^2-6u+1=0

The zeros of u^2-6u+1=0 are u=3+2sqrt(2),u=3-2sqrt(2)

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u^{2} - 6 u + 1 = 0

u = 3 + 22, u = 3 - 22

Decimal Notation

u = 5.82842 \dots, u = 0.17157 \dots

Solution steps

u^{2} - 6 u + 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 1 = 42

u_{1, 2} = \frac{- ( - 6 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 6 ) + 4 2}{2 \cdot 1}, u_{2} = \frac{- ( - 6 ) - 4 2}{2 \cdot 1}

u = \frac{- ( - 6 ) + 4 2}{2 \cdot 1} : 3 + 22

u = \frac{- ( - 6 ) - 4 2}{2 \cdot 1} : 3 - 22

The solutions to the quadratic equation are:

u = 3 + 22, u = 3 - 22

z^{2} - 3 z - 11 = - 6 z

- 75 x^{2} - 15 x - 100 = - 150 x^{2} + 10 x + 250

- 2 x^{2} - x - 6 = 0

x, - 3^{2} + x^{2} = 1 0^{2}

s^{2} + 6 s + 144

What are the solutions to the equation u^2-6u+1=0 ?
The solutions to the equation u^2-6u+1=0 are u=3+2sqrt(2),u=3-2sqrt(2)
Find the zeros of u^2-6u+1=0
The zeros of u^2-6u+1=0 are u=3+2sqrt(2),u=3-2sqrt(2)