What are the solutions to the equation roots 6x^2+12x-48 ?

The solutions to the equation roots 6x^2+12x-48 are x=2,x=-4

Find the zeros of roots 6x^2+12x-48

The zeros of roots 6x^2+12x-48 are x=2,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

6 x^{2} + 12 x - 48

x = 2, x = - 4

Solution steps

6 x^{2} + 12 x - 48

The roots are the intercepts with the x-axis

(y = 0)

6 x^{2} + 12 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 ( - 48 )}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 (- 48) = 36

x_{1, 2} = \frac{- 12 \pm 36}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 36}{2 \cdot 6}, x_{2} = \frac{- 12 - 36}{2 \cdot 6}

x = \frac{- 12 + 36}{2 \cdot 6} : 2

x = \frac{- 12 - 36}{2 \cdot 6} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

x^{2} + 97 = 20 x

- x^{2} - 20 = 0

4 x^{2} = - 144

12 x^{2} - 10 x + 2 = 0

t^{2} - 4 t + 3 = 0

What are the solutions to the equation roots 6x^2+12x-48 ?
The solutions to the equation roots 6x^2+12x-48 are x=2,x=-4
Find the zeros of roots 6x^2+12x-48
The zeros of roots 6x^2+12x-48 are x=2,x=-4