What are the solutions to the equation 3x^2-26x+16=0 ?

The solutions to the equation 3x^2-26x+16=0 are x=8,x= 2/3

Find the zeros of 3x^2-26x+16=0

The zeros of 3x^2-26x+16=0 are x=8,x= 2/3

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3 x^{2} - 26 x + 16 = 0

x = 8, x = \frac{2}{3}

Decimal Notation

x = 8, x = 0.66666 \dots

Solution steps

3 x^{2} - 26 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 3 \cdot 16}{2 \cdot 3}

(- 26)^{2} - 4 \cdot 3 \cdot 16 = 22

x_{1, 2} = \frac{- ( - 26 ) \pm 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 22}{2 \cdot 3}, x_{2} = \frac{- ( - 26 ) - 22}{2 \cdot 3}

x = \frac{- ( - 26 ) + 22}{2 \cdot 3} : 8

x = \frac{- ( - 26 ) - 22}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 8, x = \frac{2}{3}

3 x^{2} + 6 x - 132 = 0

y, x^{2} - x y + y^{2} = 6

y, x^{2} - x y + y^{2} = 9

3 a^{2} + 5 a - 28 = 0

9 x^{2} - 30 x + 28 = 0

What are the solutions to the equation 3x^2-26x+16=0 ?
The solutions to the equation 3x^2-26x+16=0 are x=8,x= 2/3
Find the zeros of 3x^2-26x+16=0
The zeros of 3x^2-26x+16=0 are x=8,x= 2/3