What are the solutions to the equation (x-2)^2-(x-2)=0 ?

The solutions to the equation (x-2)^2-(x-2)=0 are x=3,x=2

Find the zeros of (x-2)^2-(x-2)=0

The zeros of (x-2)^2-(x-2)=0 are x=3,x=2

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(x - 2)^{2} - (x - 2) = 0

x = 3, x = 2

Solution steps

(x - 2)^{2} - (x - 2) = 0

Expand

(x - 2)^{2} - (x - 2) : x^{2} - 5 x + 6

x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

x = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

x = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

6 w^{2} + w - 15 = 0

x^{2} - 2 = - \frac{7 x}{2}

0 = 0.5 F (1 - \frac{F}{3000}) - 100

- 3 t^{2} = - 8 t + 6

0.25 x^{3} - 0.25 x (x^{2} - 6 x - 30) = 21

What are the solutions to the equation (x-2)^2-(x-2)=0 ?
The solutions to the equation (x-2)^2-(x-2)=0 are x=3,x=2
Find the zeros of (x-2)^2-(x-2)=0
The zeros of (x-2)^2-(x-2)=0 are x=3,x=2