What are the solutions to the equation 3x^2+18x-81=0 ?

The solutions to the equation 3x^2+18x-81=0 are x=3,x=-9

Find the zeros of 3x^2+18x-81=0

The zeros of 3x^2+18x-81=0 are x=3,x=-9

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3 x^{2} + 18 x - 81 = 0

x = 3, x = - 9

Solution steps

3 x^{2} + 18 x - 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 ( - 81 )}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 (- 81) = 36

x_{1, 2} = \frac{- 18 \pm 36}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 36}{2 \cdot 3}, x_{2} = \frac{- 18 - 36}{2 \cdot 3}

x = \frac{- 18 + 36}{2 \cdot 3} : 3

x = \frac{- 18 - 36}{2 \cdot 3} : - 9

The solutions to the quadratic equation are:

x = 3, x = - 9

x^{2} - 4 x - 45 = 0

2 x^{2} - 25 x + 75 = 0

6 w^{2} + w - 15 = 0

x^{2} + 0.18 x - 1 0^{- 14} = 0

\frac{x ^{2}}{3} - \frac{5 x}{3} - 2 = 0

What are the solutions to the equation 3x^2+18x-81=0 ?
The solutions to the equation 3x^2+18x-81=0 are x=3,x=-9
Find the zeros of 3x^2+18x-81=0
The zeros of 3x^2+18x-81=0 are x=3,x=-9