What are the solutions to the equation 3y^2-36y-47=0 ?

The solutions to the equation 3y^2-36y-47=0 are y=(18+sqrt(465))/3 ,y=(18-sqrt(465))/3

Find the zeros of 3y^2-36y-47=0

The zeros of 3y^2-36y-47=0 are y=(18+sqrt(465))/3 ,y=(18-sqrt(465))/3

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3 y^{2} - 36 y - 47 = 0

y = \frac{18 + 465}{3}, y = \frac{18 - 465}{3}

Decimal Notation

y = 13.18795 \dots, y = - 1.18795 \dots

Solution steps

3 y^{2} - 36 y - 47 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 ( - 47 )}{2 \cdot 3}

(- 36)^{2} - 4 \cdot 3 (- 47) = 2465

y_{1, 2} = \frac{- ( - 36 ) \pm 2 465}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 36 ) + 2 465}{2 \cdot 3}, y_{2} = \frac{- ( - 36 ) - 2 465}{2 \cdot 3}

y = \frac{- ( - 36 ) + 2 465}{2 \cdot 3} : \frac{18 + 465}{3}

y = \frac{- ( - 36 ) - 2 465}{2 \cdot 3} : \frac{18 - 465}{3}

The solutions to the quadratic equation are:

y = \frac{18 + 465}{3}, y = \frac{18 - 465}{3}

2 x^{2} = - 98

(x) = - x^{2} - 2 x + 7

x^{2} - 6 x - 12

\frac{y ^{2} - 19}{4} = 3 - y

- 5 x^{2} = - 5

What are the solutions to the equation 3y^2-36y-47=0 ?
The solutions to the equation 3y^2-36y-47=0 are y=(18+sqrt(465))/3 ,y=(18-sqrt(465))/3
Find the zeros of 3y^2-36y-47=0
The zeros of 3y^2-36y-47=0 are y=(18+sqrt(465))/3 ,y=(18-sqrt(465))/3