What are the solutions to the equation 413=9x^2+2x+1 ?

The solutions to the equation 413=9x^2+2x+1 are x=(-1+sqrt(3709))/9 ,x=-(1+sqrt(3709))/9

Find the zeros of 413=9x^2+2x+1

The zeros of 413=9x^2+2x+1 are x=(-1+sqrt(3709))/9 ,x=-(1+sqrt(3709))/9

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413 = 9 x^{2} + 2 x + 1

x = \frac{- 1 + 3709}{9}, x = - \frac{1 + 3709}{9}

Decimal Notation

x = 6.65572 \dots, x = - 6.87795 \dots

Solution steps

413 = 9 x^{2} + 2 x + 1

Switch sides

9 x^{2} + 2 x + 1 = 413

Move

413

to the left side

9 x^{2} + 2 x - 412 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 9 ( - 412 )}{2 \cdot 9}

2^{2} - 4 \cdot 9 (- 412) = 23709

x_{1, 2} = \frac{- 2 \pm 2 3709}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 2 + 2 3709}{2 \cdot 9}, x_{2} = \frac{- 2 - 2 3709}{2 \cdot 9}

x = \frac{- 2 + 2 3709}{2 \cdot 9} : \frac{- 1 + 3709}{9}

x = \frac{- 2 - 2 3709}{2 \cdot 9} : - \frac{1 + 3709}{9}

The solutions to the quadratic equation are:

x = \frac{- 1 + 3709}{9}, x = - \frac{1 + 3709}{9}

y, 1 = 3 x + 2 x^{2} y^{2}

- 150 = \frac{1}{2} (- 0.98) x^{2}

8 x^{2} - 6 x = 0

2 a^{2} + 4 a - 6 = - 3 a

5 x^{2} + 13 x = - 6

What are the solutions to the equation 413=9x^2+2x+1 ?
The solutions to the equation 413=9x^2+2x+1 are x=(-1+sqrt(3709))/9 ,x=-(1+sqrt(3709))/9
Find the zeros of 413=9x^2+2x+1
The zeros of 413=9x^2+2x+1 are x=(-1+sqrt(3709))/9 ,x=-(1+sqrt(3709))/9